# 581 Shortest Unsorted Continuous Subarray

Given an integer array `nums`, you need to find one continuous subarray that if you only sort this subarray in ascending order, then the whole array will be sorted in ascending order.

Return the shortest such subarray and output its length.

Example 1:

``````Input: nums = [2,6,4,8,10,9,15]
Output: 5
Explanation: You need to sort [6, 4, 8, 10, 9] in ascending order
to make the whole array sorted in ascending order.
``````

Example 2:

``````Input: nums = [1,2,3,4]
Output: 0
``````

Example 3:

``````Input: nums = [1]
Output: 0
``````

Constraints:

• `1 <= nums.length <= 104`
• `-105 <= nums[i] <= 105`
 `````` 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 `````` ``````class Solution: def findUnsortedSubarray(self, nums: List[int]) -> int: min_val, max_val = float('inf'), float('-inf') flag = False for i in range(1, len(nums)): if nums[i] < nums[i-1]: flag = True if flag: min_val = min(min_val, nums[i]) flag = False for i in range(len(nums)-2, -1, -1): if nums[i] > nums[i+1]: flag = True if flag: max_val = max(max_val, nums[i]) l, r = 0, len(nums) - 1 while l < len(nums) and min_val >= nums[l]: l += 1 while r >= 0 and max_val <= nums[r]: r -= 1 return r-l+1 if r-l >= 0 else 0``````