Implement pow(x, n), which calculates x raised to the power n (i.e. xn).
Example 1:
Input: x = 2.00000, n = 10
Output: 1024.00000
Example 2:
Input: x = 2.10000, n = 3
Output: 9.26100
Example 3:
Input: x = 2.00000, n = -2
Output: 0.25000
Explanation: 2^(-2) = 1/(2^2) = 1/4 = 0.25
Constraints:
-100.0 < x < 100.0-231 <= n <= 231-1-104 <= xn <= 104
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class Solution:
def myPow(self, x: float, n: int) -> float:
if n == 0:
return 1
if n < 0:
return self.myPow(1 / x, -n)
res = self.myPow(x * x, n // 2)
if n % 2 == 1:
res *= x
return res
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func myPow(x float64, n int) float64 {
if n == 0 {
return 1
}
if n < 0 {
return myPow(1/x, -n)
}
result := myPow(x*x, n/2)
if n % 2 == 1 {
result *= x
}
return result
}
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