Given a string s
, return the longest palindromic substring in s
.
Example1:
Input: "babad"
Output: "bab"
Note: "aba" is also a valid answer.
Example2:
Input: "cbbd"
Output: "bb"
Constraints:
1 <= s.length <= 1000
s
consist of only digits and English letters.
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class Solution:
def longestPalindrome(self, s: str) -> str:
max_str = ''
for i in range(len(s)):
temp = self.check(s, i, i)
if len(temp) > len(max_str):
max_str = temp
temp = self.check(s, i, i+1)
if len(temp) > len(max_str):
max_str = temp
return max_str
def check(self, s: str, i: int, j: int) -> str:
while i >= 0 and j < len(s) and s[i] == s[j]:
i -= 1
j += 1
return s[i+1:j]
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func longestPalindrome(s string) string {
if len(s) < 1 {
return ""
}
start := 0
end := 0
for i := range s {
len1 := expandAroundCenter(s, i, i)
len2 := expandAroundCenter(s, i, i+1)
lenMax := -1
if len1 > len2 {
lenMax = len1
} else {
lenMax = len2
}
if lenMax > end-start+1 {
start = i - (lenMax-1)/2
end = i + lenMax/2
}
}
return s[start : end+1]
}
func expandAroundCenter(s string, left int, right int) int {
for left >= 0 && right < len(s) && s[left] == s[right] {
left--
right++
}
return right - left - 1
}
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