Write a function that reverses a string. The input string is given as an array of characters char[].
Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
You may assume all the characters consist of printable ascii characters.
Example 1:
Input: ["h","e","l","l","o"]
Output: ["o","l","l","e","h"]
Example 2:
Input: ["H","a","n","n","a","h"]
Output: ["h","a","n","n","a","H"]
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class Solution:
def reverseString(self, s: List[str]) -> None:
"""
Do not return anything, modify s in-place instead.
"""
n = len(s)
for i in range(n//2):
s[i], s[n-i-1] = s[n-i-1], s[i]
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func reverseString(s []byte]) {
i , j := 0, len(s) - 1
for i < j {
temp := s[i]
s[i] = s[j]
i++
s[j] = temp
j--
}
fmt.Println(s)
}
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public void reverseString(char[] s) {
int i = 0;
int j = s.length - 1;
while (i < j) {
char temp = s[i];
s[i++] = s[j];
s[j--] = temp;
}
System.out.println(s);
}
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