Given a 2D matrix matrix
, handle multiple queries of the following types:
Update the value of a cell in matrix
.
Calculate the sum of the elements of matrix
inside the rectangle defined by its upper left corner (row1, col1)
and lower right corner (row2, col2)
.
Implement the NumMatrix class:
NumMatrix(int[][] matrix)
Initializes the object with the integer matrixmatrix
.void update(int row, int col, int val)
Updates the value ofmatrix[row][col]
to beval
.int sumRegion(int row1, int col1, int row2, int col2)
Returns the sum of the elements ofmatrix
inside the rectangle defined by its upper left corner(row1, col1)
and lower right corner(row2, col2)
.
Example 1:
Input
["NumMatrix", "sumRegion", "update", "sumRegion"]
[[[[3, 0, 1, 4, 2], [5, 6, 3, 2, 1], [1, 2, 0, 1, 5], [4, 1, 0, 1, 7], [1, 0, 3, 0, 5]]], [2, 1, 4, 3], [3, 2, 2], [2, 1, 4, 3]]
Output
[null, 8, null, 10]
Explanation
NumMatrix numMatrix = new NumMatrix([[3, 0, 1, 4, 2], [5, 6, 3, 2, 1], [1, 2, 0, 1, 5], [4, 1, 0, 1, 7], [1, 0, 3, 0, 5]]);
numMatrix.sumRegion(2, 1, 4, 3); // return 8 (i.e. sum of the left red rectangle)
numMatrix.update(3, 2, 2); // matrix changes from left image to right image
numMatrix.sumRegion(2, 1, 4, 3); // return 10 (i.e. sum of the right red rectangle)
Constraints:
m == matrix.length
n == matrix[i].length
1 <= m, n <= 200
-105 <= matrix[i][j] <= 105
0 <= row < m
0 <= col < n
-105 <= val <= 105
0 <= row1 <= row2 < m
0 <= col1 <= col2 < n
- At most
104
calls will be made tosumRegion
andupdate
.
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