# 1200 Minimum Absolute Difference

Given an array of distinct integers `arr`, find all pairs of elements with the minimum absolute difference of any two elements.

Return a list of pairs in ascending order(with respect to pairs), each pair `[a, b]` follows

• `a, b` are from `arr`
• `a < b`
• `b - a` equals to the minimum absolute difference of any two elements in `arr`

Example 1:

``````Input: arr = [4,2,1,3]
Output: [[1,2],[2,3],[3,4]]
Explanation: The minimum absolute difference is 1.
List all pairs with difference equal to 1 in ascending order.
``````

Example 2:

``````Input: arr = [1,3,6,10,15]
Output: [[1,3]]
``````

Example 3:

``````Input: arr = [3,8,-10,23,19,-4,-14,27]
Output: [[-14,-10],[19,23],[23,27]]
``````

Constraints:

• `2 <= arr.length <= 105`
• `-105 <= arr[i] <= 106`
 `````` 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 `````` ``````import math class Solution: def minimumAbsDifference(self, arr: List[int]) -> List[List[int]]: res = [] min_diff = math.inf arr.sort() for i in range(1, len(arr)): diff = arr[i] - arr[i-1] if diff < min_diff: res = [[arr[i-1], arr[i]]] min_diff = diff elif diff == min_diff: res.append([arr[i-1], arr[i]]) return res``````